# population genetic question please help urgent?

Cerebellar abiotrophy (CA) is a recessive, genetic neurological disease found in the Arabian horse breed. If the incidence of this disease is about 1 in 400 Arabian horses, estimate the frequency of carriers in a population in Hardy-Weinberg equilibrium. The recessive allele is represented by c and the normal, wildtype allele is represented by C.

The frequency of genotype CC (homozygous normal) is represented by p2.

The frequency of genotype cc (homozygous CA) is represented by q2.

The allelic frequency of C is represented by p.

The allelic frequency of c is represented by q.

To find the frequency of carriers, we must find 2pq.

Using the equations p2+2pq+q2=1 and p+q=1 , determine the following:

Value of q2: 0.

Value of q: 0.

Value of p: 0.

Carrier Frequency: 0.

### 2 Answers

- JazSincLv 72 years agoFavorite Answer
Bad question. Your population is not in Hardy-Weinberg equilibrium for this gene locus because the afflicted are going to be selected against. Your (stupid) teacher should have used some other gene for an example question.

Let's go through the calculations anyway.

q^2 = 1/400 (given)

q^2 = 0.0025 (answer)

q = 0.05 (took the square root of the above) (answer)

p + q = 1 (given)

p = 1 - q = 1 - 0.05 = 0.95 (answer)

carrier frequency = 2pq = 2 * 0.95 * 0.05 = 0.095 (answer)

- 2 years ago
Is this from learning exercise 9?

I got the same answer as the best answer yet the system is telling me otherwise. Guess I'll try to ask the prof about this.