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# I need help with a trigonometry question?

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- Mike GLv 71 year agoFavorite Answer
θ is in Q4

r = √80 = 4√5 (Pythagoras)

sinθ = -8/[4√5] = [-2√5]/5 = (-2/5)√5

cosθ = 4/[4√5] = [√5]/5

secθ = 5/√5 = √5

sinθ + secθ = (1-2/5)√5 = 0.6√5

k = 0.6

- Φ² = Φ+1Lv 71 year ago
sinθ = -8 / √(4²+(-8)²) = -8 / (4√5) = (-2/5)√5

and secθ = √(4²+(-8)²) / 4 = (4√5) / 4 = √5

so sinθ + secθ = (-2/5)√5 + √5 = (-2/5 + 1)√5 = (3/5)√5

k = 3/5 = 0.6

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