Anonymous
Anonymous asked in Science & MathematicsPhysics · 5 months ago

A man walks 9 m to the west, and then 40 m to the north. The magnitude of the displacement of his walk is?

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  • 5 months ago
    Best Answer

    ...

    R^2 = 9^2 + 40^2 = 1681

    R = 41 m

    the angle is 12.7° W of N

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  • 5 months ago

    The resulting vector is 41m@102.6 deg.

  • Lôn
    Lv 7
    5 months ago

    Root 1681

    Answer...41 m.

  • Anonymous
    5 months ago

    Are you serious mate?

    9 m to the west is that way

    <-

    40 m to the north is that way

    ^

    |

    So the dude essentially moved 41 m to the northwest.

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