a concave mirror has a curvature of 20 cm and a 1.5 cm object is placed 5 cm away from the mirror, where is the object ? (focal point etc)?
the p or the f?
- Anonymous7 months agoFavorite Answer
focal point (distance from mirror) is:
f = r/2 = 10 cm
s = object distance from mirror
s' = image distance from mirror
1/s + 1/s' = 1/f
1/s' = 1/f - 1/s = 1/10 - 1/5 = -1/10 =
then the distance of the image (virtual) from mirror is
s' = - 10 cm (behind the mirror)
M = s'/s = - 2 (image is inverted and doubled in size)