Chemistry - Single Displacement Question?

Doing some Chemistry homework, and I got stuck on two questions and was wondering if anyone could provide any help?? It would be much appreciated.

Here is the question:

- Predicting the Products of a Single-Replacement Reaction, Based on Activity Series

Step 1 - Write the formulas of the reactants on the left of the arrow

Step 2 - Look at the Activity Series to determine if the replacement can happen

Step 3 - If the replacement can occur, complete the reaction and balance it. If the reaction cannot happen, write N.R. (no reaction) on the product side.

Now, I've got to do this for

-lead + iron (II) nitrate

and,

-cadmium + tin (IV) oxide

Can anyone help with any answers??

2 Answers

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  • 9 months ago
    Favorite Answer

    Have you got a copy of the reactivity series? Are you using this - and do you know how to use thius when answering such a question? Here is such a table

    Metal Ion

    Caesium Cs

    Francium Fr

    Rubidium Rb

    Potassium K

    Sodium Na

    Lithium Li

    Barium Ba

    Radium Ra

    Strontium Sr

    Calcium Ca

    Magnesium Mg

    Beryllium Be

    Aluminium Al

    Titanium Ti

    Manganese Mn

    Zinc Zn

    Chromium Cr

    Iron Fe

    Cadmium Cd

    Cobalt Co

    Nickel Ni

    Tin Sn

    Lead Pb

    Antimony Sb

    Bismuth Bi

    Copper Cu

    Tungsten W

    Mercury Hg

    Silver Ag

    Gold Au

    Platinum Pt

    How to interpret this in respect of your question?

    If the metal is higher in the series than the metal of the dissolved salt , then a displacement reaction will occur .

    If the metal is lower in the series than the metal of the dissolved salt , then a displacement reaction will not occur .

    Now your questions:

    -lead + iron (II) nitrate

    Pb(s) + Fe(NO3)2

    Is Pb higher in the series than Fe? Check: Pb is LOWER than Fe

    Conclusion: Reaction will not occur

    cadmium + tin (IV) oxide

    Cd + SnO2

    Is Cd higher in the series than Sn? Check : YES

    The reaction will occur

    2Cd + SnO2 → 2CdO + Sn

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  • david
    Lv 7
    9 months ago

    -lead + iron (II) nitrate

    Pb + Fe(NO3)2 --> N.R.

    -cadmium + tin (IV) oxide

    2Cd + SnO2 --> 2CdO + Sn

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