# Question: design circuit?

4. You have several 1KΩ and 6KΩ resistors. You are required to design a circuit using four resistors and a 5V power supply to provide 2V at the outputs. Note: The output will be taken across the resistor(s).

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If two 6K resistors are connected in parallel the result is 3K.

If a series string is connected :

5v, 3K, 1K, 1K, Ground. The connection between 3K and 1K will be 2 volts.

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• Anonymous
7 months ago

The loose end here is the current of the load, if there is a load.

Or is this just a simple voltage divider and the voltage divider is the load?

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• There are many ways. Besides the 6||6 and 1+1 divider, there is also

1 and 1||(1+1) ie 1K and 666.6.

or 6 and 6||12 (ie 6 and 4),

or 1.5 and 1 ( ie 1+1||1 and 1), etc.

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• You have 5v and you want to drop 3v leaving 2v.  Two 6k's in parallel = 3kΩ and two 1k's in series = 2kΩ. You connect to 6k's in parallel and connect those to 2 1k's in series across the 5v and there are 2v's across the 2 1k's

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