# Question: design circuit?

4. You have several 1KΩ and 6KΩ resistors. You are required to design a circuit using four resistors and a 5V power supply to provide 2V at the outputs. Note: The output will be taken across the resistor(s).

Relevance
• 8 months ago

If two 6K resistors are connected in parallel the result is 3K.

If a series string is connected :

5v, 3K, 1K, 1K, Ground. The connection between 3K and 1K will be 2 volts.

• Anonymous
7 months ago

The loose end here is the current of the load, if there is a load.

Or is this just a simple voltage divider and the voltage divider is the load?

• Steven
Lv 7
8 months ago

There are many ways. Besides the 6||6 and 1+1 divider, there is also

1 and 1||(1+1) ie 1K and 666.6.

or 6 and 6||12 (ie 6 and 4),

or 1.5 and 1 ( ie 1+1||1 and 1), etc.

• 8 months ago

You have 5v and you want to drop 3v leaving 2v.  Two 6k's in parallel = 3kΩ and two 1k's in series = 2kΩ. You connect to 6k's in parallel and connect those to 2 1k's in series across the 5v and there are 2v's across the 2 1k's

• qrk
Lv 7
8 months ago

When faced with a problem like this (which occurs in real design), normalize your resistor values.

If you make the lower resistor (the one with 2V across it) 1 ohm, then the upper resistor will be 1.5 ohms. With this in mind, you can solve this problem in your head (hint: multiply your normalized resistors by 2).