# 7th grade science urgent! begging for help!?

In a series circuit, there are 12 light bulbs, each providing 1 ohm of resistance. What is the total resistance?

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• 1*12=12Ω........

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• In a series circuit, resistance is added. So the requried answer=1Ohm×12=12Ohm.

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• Anonymous
7 months ago

1Ω × 12 = 12Ω

Twelve 1Ω resistors in series is 12Ω resistance.

Source(s): Been there
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• In a series circuit, that means the light bulbs are connected one after the other, resistances are added. In this case with twelve identical resistances of 1 Ohm, we can more easily say 12 x 1 Ohm = 12 Ohms.

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• What makes it "urgent?" Are you choking? Bleeding? Out of time?

Miss planning on your part does NOT constitute an urgent/emergency on our's.

• suck your mom you unhelpful **** bag. you're gonna die in 7 years anyways you wrinkly bag of bones. I bet you reek of death and little kids.

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• Rtot = 1*12 = 12 ohm

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• When light bulbs are in series, the total resistance is the sum of the resistances. This is 12 ohms.

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• Anonymous
7 months ago

Looks like somebody is going to flunk 7th grade science.

You don’t know how to add? It’s 12. There are 12 bulbs with 1 ohm of resistance in a series. In a series, you just add the resistance. In a parallel circuit, you add the inverse.

• y so t0xic dued

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• The total resistance of a series circuit is equal to the sum of individual resistances.

In a series circuit you will need to calculate the total resistance of the circuit in order to figure out the amperage. This is done by adding up the individual values of each component in series.

In this example we have three resistors. To calculate the total resistance we use the formula:

RT = R1 + R2 + R3

2 + 2 + 3 = 7 Ohms

R total is 7 Ohms

Now apply this to your problem. 🙂

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