# 4(x-5)+3=31?

How do you solve this equation

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• Remove the brackets by expanding.

4(x-5) + 3 = 31

Isolate for x.

4x - 20 + 3 = 31

4x = 31 + 20 - 3

4x = 48

Divide both sides by 4.

4x/4 = 48/4

x = 12

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• Given that 4(x-5) +3=31. opening the bracket

this becomes 4x-20+3=31..collecting like terms then simplify

this becomes 4x=31+20-3

this imply that 4x=48..dividing both sides by 4

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• Do the foil method first, so,

4x - 20 + 3 = 31

Then, isolate for variable,

4x = 31 + 20 - 3

Then simplify,

4x = 48

Then divide by 4 to solely isolate for x,

x = 12

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• 4(x - 5) + 3 = 31

4x = 48

x = 12

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• 4x - 20 + 3 = 31

4x = 31 + 20 - 3

4x = 48

x = 48/4

x = 12

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• -

4 ( x - 5 ) = 28

x - 5 = 7

x = 12

or

4x - 20 = 28

4x = 48

x = 12

or

4x - 17 = 31

4x = 48

x = 12

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• Step one: Remove the ( ) by doing the multiplication.

4X-20+3 = 31

Step two: Combine like Terms:

4X-17=31

Step Three: Add 17 to both sides of the equation

4X= 48

Step Four: Divide both sides of the equation by 4

X= 12

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• That's an easy one as you can just work back through it, undoing one stage of the calculation at a time:

4 (x-5) +3 = 31

4 (x-5) = 28

x-5 = 7

x = 12

• thanks :D

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• 4x - 20 + 3 = 31

4x = 48

x = 12

I don't know what the technique is called today. I learned how over 50 years ago.

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