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Question

A new car is tested on a 260-m-diameter track.

If the car speeds up at a steady 1.2 m/s2 , how long after starting is the magnitude of its centripetal acceleration equal to the tangential acceleration?

Answer 1

...

find target v

v^2/r = 1.2

v^2 = 1.2(260) = 312

v = 17.6635

find time to this speed

a = delta(v) / t

t = 17.6635 / 1.2 = 14.72 s

or 15 s tp 2 sig figs

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