solve the equation for the exact solutions over the interval [0,2pi) 8 tan 3x= 8?
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 ComoLv 77 months ago

tan 3 x = 1
3x = π/4 , 5π/4 , 9π/4 , 13π/4 , 17π/4 , 21π/4
x = π/12 , 5π/12 , 3π/4 , 13π/12 , 17π/12 , 7π/4
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 Wayne DeguManLv 77 months ago
tan3x = 1
i.e. 3x = π/4 + nπ....for n = 0, 1, 2,...
so, x = π/12 + nπ/3
=> x = π(1 + 4n)/12
Then, with n = 0, 1, 2,...we have:
x = π/12, 5π/12, 9π/12, 13π/12, 17π/12 and 21π/12...for [0, 2π)
:)>
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