I need help with algebra yes I have tried to figure it out ?
Penny made a 74% on her first test.What must she get on her next test to have an average of at least 80% (100 points per test)?
Write an equation
- 1 month agoFavorite Answer
(0.74+x)/2 = 0.8
The average is equal to the sum of the values divided by the number of things you added... so 74% (or 0.74 as a decimal) plus x (what her next test percentage should be, as a decimal) equals her desired test average, or 80% (0.8).
When you solve this equation, you get 0.86, or 86%. Thus, she must get at least an 86 on her next test...hope this helpedSource(s): high school experience lol
- JoeLv 51 month ago
Try to figure it out.
- DavidLv 71 month ago
Let x be percentage of next test and so if (74+x)/2 = 80 then x = 86%
- VPLv 71 month ago
You could also have done it using a bit of logic.
1. You know that each test is based on 100%.
2. You know Penny got a 74 on the 1st test.
3. You know that 74 is 6 less than 80.
That would mean she'd have to score 6 MORE than 80 on the next test, which is an 86. That would balance things out. She was 6 less than 80 on the 1st test; she needs to be 6 over 80 on the 2nd test.
Equation: (x + y) / 2 = 80; x = 74; Solve for y
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- SumDudeLv 71 month ago
86%.... lucky guess
- John DDLv 71 month ago
2 tests, max 200 points
80% of 200 = 160
so she needs 160 - 74 = 86 points on her second test
- Anonymous1 month ago
It’s always 42