# chem help?

a gaseous mixture made of 6.00g of 02 and 9.00g of CH4 is placed in a vessel at 0c. what is the partial pressure of each gas and what is the total pressure in the vessel? the volume of vessel is 10.0l.

### 1 Answer

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- az_lenderLv 73 weeks ago
That's 0.375 moles of O2 and 0.5625 moles of CH4.

p = nRT/V

= (0.9375 mol)(8.314 Pa*m^3/molK)(273.15 K)/(0.01 m^3)

= about 200 kPa but use a calculator.

Then the partial pressures can be found,

because the O2 exerts 6/15 = 2/5 of the pressure,

and the methane exerts 9/15 = 3/5 of the total pressure.

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is it 0.9375*8.314*273.15/0.01=21.290