At the bottom of a mine shaft, the air pressure is 138000 Pa. How deep is the mine? (Unit = m) 1 atm = 101300 Pa Pair = 1.29 kg/m^3?
- oubaasLv 712 months ago
P-Pa = h*g*ρ
h = (138,000-101,300)/(9.806*1.29) = 2900 m
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