How many gs of ammonium sulfate can be produced if 30 mol of H2SO4 react with excess NH3 according to the equation 2NH3+ H2SO4 → (NH4)2SO4?

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  • 3 weeks ago

    The molar mass of the product is 2(14.0) + 8(1.008) + 32.0 + 4(16.0) = 132.1 g/mol 

    30 mol H2SO4 X (1 mol (NH4)2SO4 / 1 mol H2SO4) X 132.1 g/mol = 3.96X10^3 g (NH4)2SO4

    (Formally, your answer should have only 1 or 2 significant figures, and so should be expressed as 4000 or 4.0X10^3 grams)

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