Decomposition of hydrogen peroxide, percentage yield of oxygen is 93%. What is the actual yield gm of oxy if you start with 100. g H2O2?  ?

2H2O2→ 2H2O + O2.

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  • 3 weeks ago
    Favorite Answer

    (100. g H2O2) / (34.015 g H2O2/mol) x (1 mol O2 / 2 mol H2O2) x (0.93) x (31.99886 g O2/mol) = 43.7 g O2

  • david
    Lv 7
    3 weeks ago

    100  X  (32/34) X 0.93  =  87.5 g O2

  • 3 weeks ago

    Hydrogen Peroxide ➜ Water + Oxygen

    2H₂O₂ ➜ 2H₂O + O₂

    2 moles of H₂O₂ ➜ 2 moles of water + 1 mole of O₂

    68 g of H₂O₂ ➜ 36 g of water + 32 g of O₂

    Assuming that "93%" means 93% of theoretical yield

    given the 93% number, 68 g of H₂O₂ would yield 0.93•32 g of O₂, or 29.76 g

    so the ratio is 29.76/68

    and x/100 = 29.76/68

    x = 51.3 g

    OR assuming that "93%" means 93% actual yield, then answer is 93 g

  • 3 weeks ago

    Why is this posted under Business/Personal Finances?

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