# Algebra 2 Question help?

Parabola: x=-3 is axis of symmetry, 2 points on the graph: (-5,1) & (1,7).

Find this Function in vertex form.

### 4 Answers

- MyRankLv 63 weeks ago
y = a(x - h)² + k

y = a(x + 3)² + k on (-5, 1) & (1, 7)1 = a(-5 + 3)² + k1 = 4a + kk = 4a - 1 ... (1)7 = a(1 + 3)² + 4a - 17 = 16a + 4a - 18 = 20aa = 2/5 → (k = 3/5) from (1)y = 2/5 (x + 3)² + 3/5.

Source(s): https://myrank.co.in/ - Φ² = Φ+1Lv 73 weeks ago
The parabola with vertical LOS, Vertex (-3,b) and passing through (-5,1) is y = (1-b)/(-5--3)² (x--3)² + b = (1-b)/4 (x+3)² + b.

The parabola with vertical LOS, Vertex (-3,b) and passing through (1,7) is y = (7-b)/(1--3)² (x--3)² + b = (7-b)/16 (x+3)² + b.

(1-b)/4 = (7-b)/16 when b = -1, so the equation is y = 1/2 (x+3)² - 1.

Source(s): The quadratic equation of the curve with the vertex at (x₀,y₀), with a line of reflection parallel to the y axis and passing through (x₁,y₁) is y = (x-x₀)²(y₁-y₀)/(x₁-x₀)² + y₀ - ted sLv 73 weeks ago
standard form yields y = A ( x + 3)² + W...( - 5 , 1 ) implies 1= A(4) + W and (1 , 7 ) implies 7 = A (16) + W....solve the system...{ 1 / 2 ; - 1 }