# an object of volume 0.0882 m^3 is immersed in a fluid; it experiences a buoyant force of 671 N. What is the density of the fluid?

### 2 Answers

Relevance

- MyRankLv 611 months ago
Given,

Volume (V) = 0.0882m³Force (F) = 671NDensity (ρ) = ?Acceleration due to gravity (g) = 9.81m/sec²We know that:-Density (ρ) = mass (m) / volume (v) = (force (F) / g) / volume (v) ∵ F=mg= (671N/9.81m/sec²) / 0.0882m³= 775.5kg/m³ ≈ 776kg/m³.

Source(s): https://myrank.co.in/ - oldschoolLv 711 months ago
The "buoyant force" is the weight of the fluid displaced or moved out of the way = mass of fluid * g. = 671N

So mass of fluid = 671/9.8 = 68.5kg. Now we know the mass and the volume is given so Density = Mass/Volume

Density = 68.5/0.0882 = 776kg/m³

Still have questions? Get your answers by asking now.