Anonymous
Anonymous asked in Science & MathematicsMathematics · 3 weeks ago

# A math problem, but not really?

Trying to figure this out:

If a ferry that travels 25 mph can get from one point to another in 50 minutes, how long will it take for a sailboat that can go 5 mph to reach the same destination?

Thank you! :)

Relevance

We know distance = speed x time

Since distance for both ferry and sail boat is same, we get

25 mph x (50/60)h = 5 mph x time for sail boat

time for sail boat = 25 x (50/60) / 5 =  25/6 h = 4⅙ h = 4 hr 10 min

• 50/5=5

50*5=250 min=4.1667 hrs

• 250 mins. or x=250

• Depends on which way the wind blows.

•

A ferry that travels 25 mph can get from one point to another in 50 minutes.

Distance covered is 125/6 or 20 5/6 miles.

It will take 4 hours 10 minutes for a sailboat that can go 5 mph

to reach the same destination.

• Since sailboat's rate is (1/5)th of ferry's rate it will take 5 times as long as the ferry

to go the same distance, ie., 250 min. (= 4hrs, 10 min.)

Source(s): Self.
• Hey, I know you are all the time kidding.

• [ 25 x 5/6] / 5 = 25 / 6 = ===> 4 hours 10 min

• 25/5 = x/50

cross multiply

5x = 1250

x = 250

• 250 minutes. It is a math problem.

5 times slower = 5 times the duration