If the mass is 4.3 kg, the initial speed is 4.0 m/s, and the initial height is 8.0 m, find speed of the ball when it is at height of 7.6 m.?
- MyRankLv 67 months ago
Mass (m) = 4.3kg
Initial speed (u) = 4m/sec
Initial height (hi) = 8m
Final speed (v) = ?
Final height (hf) = 7.6m
Using kinematic relation:-
v² = u² + 2gh (hi – hf)
= final speed (v) = √u² + 2g(hi – hf)
= √(4m/sec)² + 2 x 9.81m/sec² (8m-7.6m)
= √16m²/sec² + 7.848 m²/sec²
= 4.88m/sec ≈ 4.9m/sec
∴ final speed (v) = 4.9m/secSource(s): http://myrank.co.in/
- PinkgreenLv 78 months ago
Let the new speed of the ball be v m/s, then
v=sqr(23.848)=4.9 m/s approximately.
- oubaasLv 78 months ago
Conservation of energy shall apply :
V = √Vo^2+2*g*(ho-h) = √4^2+19.612*(8-7.6) = 4.88 m/sec
- billrussell42Lv 78 months ago
depends on the angle. Is the ball thrown upwards, downwards, or at an angle?