# Math question?

Find k so that the line containing points (-3,k) and (6,6) is parallel to the line containing the points (5,5) and (1,-2)

How do I find k???

### 7 Answers

- 2 weeks ago
slope of the line passing (5,5) and (1,-2)

m = (y1 - y2) / (x1 - x2) = (5 + 2) / (5 - 1) = 7/4

slope of the line passing (-3,k) and (6,6)

m = 7/4 = (k - 6) / (-3-6)

7 (-9) = 4 (k-6)

- 63 = 4k - 24

4k = - -39

k = -39/4

- DavidLv 72 weeks ago
Slope of points:(5, 5) and (1, -2) = 7/4

Slope of parallel points: (-3, k) and (6, 6) = 7/4

If: (k-6)/(-3-6) = 7/4

Then: k = -39/4 or -9.75

Check: (-9.75-6)/(-3-6) = 7/4

- ?Lv 73 weeks ago
The line containing the points (5,5) and (1,-2) has slope

..............5 - (-2).....7

.....m₁ = ---------- = ---

..............5 - 1.........4

The parallel line passing through (-3,k) and (6,6) must have

slope equal to m₁

.....m = m₁

.....k-6......7

.....----- = ----

.....-3-6.....4

4k - 24 = -21 - 42

4k = -39

......-39

k = ----

........4

k = -9.75...............ANS

- Iggy RockoLv 73 weeks ago
(6 - k)/(6 - -3) = (-2 - 5)/(1 - 5)

(6 - k)/9 = -7/-4

-4(6 - k) = 9(-7)

-24 + 4k = -63

4k = -39

k = -39/4

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- az_lenderLv 73 weeks ago
You need

(5 - (-2))/(5 - 1) = (6 - k)/(6 - (-3)) =>

7/4 = (6-k)/9 =>

6 - k = 63/4 =>

k = 6 - 63/4 = (24-63)/4 = -39/4 = -9.75.

Check my arithmetic

- Jim MoorLv 73 weeks ago
Parallel means the slopes are the same

find the slope for (5,5) and (1,-2)

Slope = (5+2)/(5-1) 7/4

then make the slope the same for (-3,k) and (6,6)

7/4 = (k-6)/(-3-6)

solve and you have the value for k

Thanks!!! I think the answer being a fraction/decimal totally threw me off. I thought I was doing it wrong haha thank you!!