The electric potential energy of an electron near a silicon nucleus (charge +14e) is −1.27 ✕ 10−16 J. What is the distance between the electron and the nucleus?
- billrussell42Lv 72 months agoFavorite Answer
−1.27 ✕10–16 = –12.7–16 = –28.7 J. ??
1 electron charge = 1.602e-19 C
Potential energy between two charges, in Joules
U = kQ₁Q₂/r
Q₁ and Q₂ are the charges in coulombs
r is separation in meters
k = 8.99e9 Nm²/C²
(9e9)(1.602e-19)(14•1.602e-19) / d = 28.7
d = (9e9)(1.602e-19)(14•1.602e-19) / 28.7 = _____ m