SAMMM asked in Science & MathematicsPhysics · 8 months ago

A 531 g ball strikes a wall at 15.6 m/s and rebounds at 10.4 m/s. ?

 The ball is in contact

with the wall for 0.032 s.

What is the magnitude of the average force

acting on the ball during the collision?

Answer in units of N.

3 Answers

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  • Anonymous
    8 months ago
    Favorite Answer

    m*ΔV = F*Δt

    F = m*ΔV/Δt = 0.531*(15.6+10.4)*1000/32 = 431 N

  • MyRank
    Lv 6
    7 months ago

    Given,

    Mass (m) = 531grams = 0.531kg 

    Initial speed (u) = 15.6m/sec 

    Final speed (v) = 10.4m/sec 

    Time (t) = 0.032sec 

    Magnitude of average force (F) = ? 

    We know that:- 

    Impulse (I) = change in momentum (∆p) 

    Force (F) x time (t) = mass x change in velocity 

    Force (F) = 0.531kg x (15.6 + 10.4)m/sec / 0.032sec = 431N

    ∴ Force (F) = 431N

  • Anonymous
    8 months ago

    change in momentum = impulse

    change in momentum = mass * change in speed

    impulse = force * time

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