# A grocery shopper tosses a(n) 8.2 kg bag of rice into a stationary 19.8 kg grocery cart.?

The bag hits the cart with a horizontal speed

of 6.4 m/s toward the front of the cart.

What is the final speed of the cart and bag?

Answer in units of m/s.

### 2 Answers

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- Anonymous2 months agoFavorite Answer
Momentum conservation shall apply :

mb*Vb = (mb+mc)*Vc

Vc = 8.2*6.4/(8.2+19.8) = 1.87 m/sec

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- alexLv 72 months ago
Conservation of momentum

---> 8.2(6.4) = (19.8+8.2)v

solve for v

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