A grocery shopper tosses a(n) 8.2 kg bag of rice into a stationary 19.8 kg grocery cart.?
The bag hits the cart with a horizontal speed
of 6.4 m/s toward the front of the cart.
What is the final speed of the cart and bag?
Answer in units of m/s.
- Anonymous2 months agoFavorite Answer
Momentum conservation shall apply :
mb*Vb = (mb+mc)*Vc
Vc = 8.2*6.4/(8.2+19.8) = 1.87 m/sec
- alexLv 72 months ago
Conservation of momentum
---> 8.2(6.4) = (19.8+8.2)v
solve for v