Kylie asked in Science & MathematicsChemistry · 10 months ago

What pressure is required to reduce 75 mL of a gas at standard conditions to 11 mL at a temperature of 27◦C? Answer in units of atm.?

3 Answers

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  • 10 months ago

    If "standard conditions" means 1 atm and 0C, the answer will be

    (1 atm)*(75/11)*(303.15/273.15)

    = about 7 atm but use a calculator.

    If "standard conditions means 1 bar and 0C, the answer will be

    (1 bar)(75/11)(303.15/273.15)*(1 atm/1.013 bar)

    = again near 7 atm.

  • 10 months ago

    (1 atm) x (27 + 273) K / (273 K) x (75 mL / 22 mL) = 3.7 atm

  • Jim
    Lv 7
    10 months ago

    PV = nRT <<<memorize, you'll need it.

    Since nR are constant, PV/T init = PV/T final

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