how many moles of sulfur hexafluoride are made.?

If 0.555 mol of sulfur are reacted with 1.20 mol of fluorine gas, how many moles of sulfur hexafluoride are made? Balance and identify the limiting reagent.

S(s)+F2(g)---> SF6(g)

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  • 8 months ago

    S(s) + 3 F2(g) → SF6(g)

    1.20 moles of F2  would react completely with 1.20 x (1/3) = 0.40 mole of S, but there is more S present than that, so S is in excess and F2 is the limiting reagent.

    (1.20 mol F2) x (1 mol SF6 / 3 mol F2) = 3.60 mol SF6

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