A bird is flying with a speed of 15.2 m/s over water when it accidentally drops a 2.10 kg fish.?
A bird is flying with a speed of 15.2 m/s over
water when it accidentally drops a 2.10 kg
The acceleration of gravity is 9.81 m/s
If the altitude of the bird is 8.40 m and air
resistance is disregarded, what is the speed of
the fish when it hits the water?
Answer in units of m/s.
- Anonymous8 months ago
Energy conservation shall apply :
m/2*Vf^2 = m/2*Vi^2+m*g*h
mass m cross and all terms are multiplied by 2
Vf = √
Vi^2+2gh = √
15.2^2+19.62*8.4 = 19.9 m/sec
- AshLv 78 months ago
horizontal velocity of fish will be the same as the bird, Vh = 15.2 m/s
Vertical velocity of the bird can be calculated as below
Vv² = u² + 2gs
Vv² = 0² + (2*9.81*8.40)
Vv² = 2*9.81*8.40
speed of the fish will be = √(Vh²+Vv²) = √[15.2²+(2*9.81*8.40)] = 19.9 m/s