# A bird is flying with a speed of 15.2 m/s over water when it accidentally drops a 2.10 kg fish.?

A bird is flying with a speed of 15.2 m/s over

water when it accidentally drops a 2.10 kg

fish.

The acceleration of gravity is 9.81 m/s

2

.

If the altitude of the bird is 8.40 m and air

resistance is disregarded, what is the speed of

the fish when it hits the water?

Answer in units of m/s.

### 2 Answers

Relevance

- Anonymous8 months ago
Energy conservation shall apply :

m/2*Vf^2 = m/2*Vi^2+m*g*h

mass m cross and all terms are multiplied by 2

Vf = √

Vi^2+2gh = √

15.2^2+19.62*8.4 = 19.9 m/sec

- AshLv 78 months ago
horizontal velocity of fish will be the same as the bird, Vh = 15.2 m/s

Vertical velocity of the bird can be calculated as below

Vv² = u² + 2gs

Vv² = 0² + (2*9.81*8.40)

Vv² = 2*9.81*8.40

speed of the fish will be = √(Vh²+Vv²) = √[15.2²+(2*9.81*8.40)] = 19.9 m/s

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