Anonymous
Anonymous asked in Science & MathematicsMathematics · 8 months ago

# Find an equation for the line that passes through the points (−5,-3) and (3, 3)?

Relevance
• 8 months ago

solving for the slope

m = (y₂ - y₁ )/(x₂ - x₁)

m = [3 - (-3)]/[3 - (-5)]

m = (3 + 3)/(3 + 5)

m = 6/8 or 3/4

apply point slope form

y - y₁ = m(x - x₁)

y - (-3) = 3/4[x - (-5)]

y + 3 = 3/4(x + 5)

4(y + 3) = 3(x + 5)

4y + 12 = 3x + 15

4y = 3x + 15 - 12

4y = 3x + 3

y = 3/4x + 3/4 answer//

The equation of the line is y = 3/4x + 3/4

• 8 months ago

y- - 3 = (3--3)/(3--5)(x - -5)

y + 5 = (6)/(8)(x + 5)

y + 5 = )3/4)(x + 8)

y + 5 = 3x/4 + 24/4

y = 3x/4 + 6 - 5

y = 3x/4 + 1

or

4y = 3x + 4

or

4y -3x = 1

or

4y - 3x - 1 = 0

• Philip
Lv 6
8 months ago

A(-5,-3), B(3,3). Slope AB = (3+3)/(3+5) = (3/4).

Let line L: y = (3/4)x + b...(1). B is on L. Therefore

3 = (3/4)3 +b, ie., b =3[1-(3/4)] = 3(1/4) = (3/4).

Then L: y = (3/4)x + (3/4) {slope, y-intercept} or

L: 3x -4y +3 = 0 {standard}.

• David
Lv 7
8 months ago

Points: (-5, -3) and (3, 3)

Slope: 3/4 or 0.75

Equation: y = 0,75x +0.75

• MyRank
Lv 6
8 months ago

A(-5, -3), B(3, 3)

y - y₁ = y₂-y₁/x₂-x₁ (x-x₁)

y-(-3) = 3-(-3) / 3-(-5) (x+5)

y+3 = 6/8 (x+5)

y+3 = ¾ (x+5)

4(y+3) = 3(x+5)

4y + 12 = 3x + 15

3x-4y+3 = 0

• 8 months ago

(3--3)x - (3--5)y = 3×-5 - 3×-3 which is 6x - 8y = -6 which simplifies to 3x - 4y = -3.

Source(s): An equation of the line through the points (x₁,y₁) and (x₂,y₂) is (y₁-y₂)x - (x₁-x₂)y = y₁×x₂ - x₁×y₂
• rotchm
Lv 7
8 months ago

Apply the exact same reasoning already given to you numerous times in: