Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 month ago

Physics: Can you help with number 9?

How did he get 12.5m/s?

(Number 8 ties in with number 9)

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  • 1 month ago
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    Assign all quantities towards Sally to be negative, and in the direction of shooting out from Sally to be positive.

    Assign the asteroid to be "1", and the cable to be "2".

    m₁ = 85 kg, m₂ = 10 kg

    Initial: u₁ = -17.0 m/s, u₂ = 25 m/s

    FinalL v₁ = v₂ = v

    Total initial momentum = Total final momentum

    m₁u₁ + m₂u₂ = (m₁ + m₂)v

    85×(-17.0) + 10×25 = (85 + 10)v

    v = [85×(-17.0) + 10×25] / (85 + 10)

    Final velocity v = -12.6 m/s

    (The negative sign shows that the direction is towards Sally.)

    The momentum of the asteroid-cable after the cable impacts with the asteroid

    = (85 + 10) × (-12.6)

    = -1200 kg•m/s

    (The negative sign shows that the direction is towards Sally.)

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  • Anonymous
    1 month ago

    8)

    Vs = 25*10/55 = 50/11 of m/sec

    9)

    final momentum M = 85*17-10*25 = 1195 kg*m/sec

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  • Dylan
    Lv 6
    1 month ago

    Question 9 asks for the momentum of the asteroid + cable after the impact so 12.5 m/s is actually wrong, it is asking for momentum not velocity.

    Momentum before the collision is the same as after the collision.

    Ma*Va + Mc*Vc

    The cable is moving at 25 m/s away from sally and the asteroid is moving towards sally at 17 m/s, the weight of both is given.

    85*17 + 10*(-25)

     = 1195 kg m/s

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