If 0.53g of pure anhydrous sodium carbonate is dissolved in water to make 200cm^3 of solution . What is the concentration of the solution .?
- pisgahchemistLv 72 months ago
You can express "concentration" in a number of units, and you don't specify which:
g / mL or g / cm³ ...... using 1 mL = 1 cm³
g / 100 mL ... solubility
mol / L ... molarity
mol / kg of water ..... molality
In chemistry, molarity is probably the most common single concentration unit:
0.53g Na2CO3 x (1 mol Na2CO3 / 105.99g Na2CO3) / 0.200L = 0.025 mol Na2CO3 / 1 L ... or ... 0.025M
Since the precision of "200 mL" is ambiguous, and 0.53g is expressed to two significant digits, the answer can be no more precise than two significant digits.
- Anonymous2 months ago
It's a simple division unless you need a specific set of units which you didn't specify.
- billrussell42Lv 72 months ago
that is 105.9888 g/mol, call it 106.
0.53 g / 106 g/mol = 0.005 mol200 cm³ = 200 mL = 0.2 Lmolar concentration is number of moles per liter0.005 mol / 0.2 L = 0.025 mol/L = 0.025 M