How far is the spring stretched from its original length?

A weight of 12.0 N hangs motionless from a spring, with a spring constant of 10.0 N/m.

0.120 m

0.220 m

0.833 m

1.20 m

3 Answers

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  • 2 months ago
    Favorite Answer

    F = kx

    x = F/k = 12/10 = 1.20 m

  • 4 weeks ago

    12.0 N (1m/10.0N) = 1.20 m

    no formula needed

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  • MyRank
    Lv 6
    2 months ago

    Given,

    Force (F) = 12N

    Spring constant (K) = 10N/m

    Distance (x) =?

    We know that:-

    Force (F) = kx

    Distance (x) = F/K = 12N/10N/m = 1.2m

    ∴ Distance (x) = 1.2m.

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