A parallel-plate capacitor has a charge of 6.0 µC Whedon charged by a potential diferente Energy of 1.25.?
- Anonymous8 months ago
charge Q = C*V
capacitance C = Q/V = 6.0*10^-6/1.25 = 4.8 µF
stored energy E = C/2*V^2 = 2.4*10^-6*1.25^2 = 3.75 µjoule
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