Mario asked in Science & MathematicsPhysics · 8 months ago

A parallel capacitor has a charge of 6.0 µC When charged by a potential diferente of 1.25 V.?

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  • Anonymous
    8 months ago

    charge Q = C*V

    capacitance C = Q/V = 6.0*10^-6/1.25 = 4.8 µF

    stored energy E = C/2*V^2 = 2.4*10^-6*1.25^2 = 3.75 µjoule

  • 8 months ago

    Q = CV

    C = Q/V

    C = 6e-6/1.25

    C = 4.8e-6

    C = 4.8 uF

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