A parallel capacitor has a charge of 6.0 µC When charged by a potential diferente of 1.25 V.?
- Anonymous3 weeks ago
charge Q = C*V
capacitance C = Q/V = 6.0*10^-6/1.25 = 4.8 µF
stored energy E = C/2*V^2 = 2.4*10^-6*1.25^2 = 3.75 µjoule
- derframLv 73 weeks ago
Q = CV
C = Q/V
C = 6e-6/1.25
C = 4.8e-6
C = 4.8 uF
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