Find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 22?

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  • 4 weeks ago

    Let the 3 odd numbers be

    x-2, x, x+2

    x-2+2x+3(x+2)=22

    =>

    6x+4=22

    =>

    6x=18

    =>

    x=3

    =>

    the numbers are 1,3,5.

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  • 4 weeks ago

    2n + 1 +2(2n + 3) + 3(2n + 5) = 22

    2n + 1 + 4n + 6 + 6n + 15 = 22

    12n + 22 = 22

     12n = 22 - 22

     12n = 0

     n = 0

    1st odd integer  = 2n + 1 = 2(0) + 1 = 1 answer//

     2nd odd integer = 2n + 3 = 2(0) + 3 = 3 answer//

    3rd odd integer = 2n + 5 = 2(0) + 5 = 5  answer//

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  • 4 weeks ago

    the integers are "consecutive and odd" so call them

    2n + 1, 2n+3 and 2n+5

    hence 

    2n+1 + 4n+6 + 6n + 15 = 22

    ==> 12n + 22 = 22

    ==> n = 0

    so 

    1, 3 and 5

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  • 4 weeks ago

    the three consecutive odd integers are 1 and 3 and 5.

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  • 1 month ago

    The average of these numbers is 22/6 = 3⅔ and this is going to fall between the second and third odd integers, so the three odd integers are 1, 3, and 5.

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  • 1 month ago

    Three consecutive odd integers such that 

    the sum of the first, two times the second, 

    and three times the third is 22:

    (x - 2) + 2x + 3(x + 2) = 22

    x = 3

    Answer: 1, 3 and 5.

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  • 1 month ago

    We want three consecutive odd integers.  If we call the middle number "x", then the ones before and after it are (x - 2) and (x + 2).

    The sum of the first, two times the second, and three times the third is 22:

    (x - 2) + 2x + 3(x + 2) = 22

    Simplify and solve for x:

    x - 2 + 2x + 3x + 6 = 22

    6x + 4 = 22

    6x = 18

    x = 3

    That's your middle number, so the other two are:  1 and 5

    Your three numbers are:

    1, 3, and 5.

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  • 1 month ago

    1,3,5.

    1 + 2*3 + 3*5 = 22.

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  • 1 month ago

    The integers are 1, 3, and 5. Because 1 + 6 + 15 = 22.

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  • Your integers will be x - 2 , x , x + 2

    (x - 2) + 2 * x + 3 * (x + 2) = 22

    x - 2 + 2x + 3x + 6 = 22

    6x + 4 = 22

    6x = 18

    x = 3

    1 , 3 , 5

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