A box of mass 95.1 g accelerates from velocity +24.5 m/s to velocity +32.2 m/s as it moves distance 61.7 m. Find the net force Fnet, in Newtons, acting on the box. The direction of the force is given by the sign of the answer..
- Anonymous1 month ago
acceleration a = (Vf^2-Vi^2)/2d = (32.2^2-24.5^2)/(61.7*2) = 3.5380 m/sec^2
Fnet = m*a = 0.0951*3.5380 = 0.336 N