Hope to get some help on this Grade 6 question.. Hopefully not a need to use algebra to solve, since just learned algebra?

Update:

nephew learnt basic algebra only. so i'm trying to find an easier way to explain to him... creating two unknowns to solve is not part of the syllabus at the moment 

Attachment image

4 Answers

Relevance
  • Philip
    Lv 6
    1 month ago
    Favorite Answer

    Total number of pairs of shoes produced = 850. SP = 'sellng price of'.

    SP female pair = $45. SP male pair = $39. Let m = number of male pairs sold.

    Then amount collected from sale of m male pairs = $(39*m)...(1).

    Also, amount collected from sale of (850-m) female pairs =$45(850-m) =$(39*m) +

    $(12210). Then 45(850-m) = 39m + 12210, ie., m(39+45) = 45*850 -12210, ie., 

    84m = 38250 -12210 = 26040 and m = 310. Then (1) above --->$(39*m) = $(39*310)

    = $12090 = $12,100 (rounded to nearest $100.) was collected from the sale of the

    male shoes.

    • Commenter avatarLogin to reply the answers
  • sepia
    Lv 7
    1 month ago

    There were 850 pairs of shoes produced in a factory. Each pair of female shoes was sold at $45. Each pair of male shoes was sold at $39. When all the shoes were sold , the amount of money collected from the sale of female shoes was $12210 more than the amount of money collected from the sale of male shoes. How much money was collected from the sale of male shoes?  

    x + y = 850

    45y - 39x = 12210

    45x + 45y = 38250

    84x = 26040

    x = 310

    39x = 12090

    $12100 was collected from the sale of male shoes.

    (answer rounded to the nearest hundred dollars).

    • Hirq1 month agoReport

      nephew learnt basic algebra only. so i'm trying to find an easier way to explain to him... creating two unknowns to solve is not part of the syllabus at the moment 

    • Commenter avatarLogin to reply the answers
  • 1 month ago

    That's why you have algebra homework because this is practice for what you should have learned in class.

    Let f = pairs of female shoes sold

    Let m = pairs of male shoes sold

    We know there are 850 pairs of shoes sold so we can create this equation:

    f + m = 850

    We are then told that female shoes are sold for $45 each and male shoes are sold for $39 each.  So when "f" shoes are sold, (45f) dollars have been collected.  When "m" shoes are sold, (39m) dollars have been collected.  We are told that the money collected from the female shoes is $12,210 more than the amount collected for the male shoes.  We can use this information to create this equation:

    45f = 12210 + 39m

    We now have a system of two equations and two unknowns so we can find out how many pairs of each type of shoe was sold.

    If we solve the first equation for f in terms of m we can then substitute that into the other equation and solve for the remaining unknown:

    f + m = 850

    f = 850 - m

    45f = 12210 + 39m

    45(850 - m) = 12210 + 39m

    38250 - 45m = 12210 + 39m

    26040 = 84m

    310 = m

    We can find "f" if we wanted, but we are asked to find how much money was collected from the men's shoe sales rounded to the nearest hundred.  We know "m", so the total amount collected from above is (39m):

    39m

    39 * 310

    12090

    Rounded to the nearest hundred:

    $12,100

    • Hirq1 month agoReport

      nephew learnt basic algebra only. so i'm trying to find an easier way to explain to him... creating two unknowns to solve is not part of the syllabus at the moment 

    • Commenter avatarLogin to reply the answers
  • Anonymous
    1 month ago

    Yes, you need algebra.  Unless you prefer to guess.

    • Commenter avatarLogin to reply the answers
Still have questions? Get your answers by asking now.