find the equation of the line passing through points (2,4) and (3,2)?

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  • 1 month ago

    First find the gradient (m)

    m = [2 - 4]/{3-2] = -2/1 = -2

    Displace (x,y) against any one point and using the gradient.

    y - 4 = -2(x - 2)

    y - 4 = -2x + 4

    y = -2x + 8

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  • 1 month ago

    Gradient => (2 - 4)/(3 - 2) = -2

    so, equation is y = -2x + c

    Using point (2, 4) we have:

    4 = -2(2) + c

    i.e. c = 8

    Hence, y = -2x + 8

    or, y + 2x - 8 = 0

    :)>

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  • Jeremy
    Lv 6
    1 month ago

    Point A: Ax = 2, Ay = 4; Point B: Bx = 3, By = 2.

    Two-point form: (y - By)/(Ay - By) = (x - Bx)/(Ax - Bx).

    Hence: (y - 2)/(4 - 2) = (x - 3)/(2 - 3) => (y - 2)/2 = (x - 3)/(-1) => (y - 2)/2 = 3 - x =>

    => y - 2 = 2(3 - x) => y - 2 = 6 - 2x => y = -2x + 6 + 2 => ANSWER: y = -2x + 8.  

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  • 1 month ago

    Equation of the straight line (two-point form) :

    (y - 4)/(x - 2) = (2 - 4)/(3 - 2)

    (y - 4)/(x - 2) = -2

    y - 4 = -2(x - 2)

    y - 4 = -2x + 4

    2x + y - 8 = 0

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  • David
    Lv 7
    1 month ago

    Points: (2, 4) and (3, 2)

    Slope: -2

    Equation: y = -2x+8

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