Prove that segment BC is congruent to segment AD?
- PinkgreenLv 71 month ago
The given conditions are not clear. I understand your problem as that
AB // CD
are given, & prove that BC=AD. If so, then
AB//CD=><ADB=<BDC (alternate angles equal)
BD=BD (common sides equal)
Thus, Tri. BCD is congruent to tri. DAB (A.S.A)
BC=AD (the corresponding sides of 2 congruent triangles equal)
- sepiaLv 71 month ago
Obviously, BC = AD, AB = DC,
and ∠CBD = ∠ADB.
- KrishnamurthyLv 71 month ago
In the figure itself it is seen that the line segment BC
is equal to the line segment AD.
- PuzzlingLv 71 month ago
Well, they are already given as congruent in the diagram so technically a proof is unnecessary.
If they weren't marked as congruent, you would say:
AB || CD --- Given
∠ADB ≅ ∠CBD --- Given
DB ≅ BD --- Reflexive property
∠ABD ≅ ∠CDB --- When a transversal (DB) cuts parallel lines, alternate interior angles are congruent.
△ADB ≅ △CBD --- ASA (angle-side-angle) triangle congruence postulate
BC ≅ AD --- Corresponding parts of congruent triangles are congruent (CPCTC)
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- Anonymous1 month ago
You have a parallelogram since by the alternate angle theorem, BC is parallel to AD.
Property of a parallelogram is that opposite sides are equal, so BC = AD
- 1 month ago
Something is not right with the question, "congruent" is not used for line segments, only triangles (or other polygons), as far as I know. In the diagram it is given that the segments BC and AD are equal.
I'm assuming you meant "prove triangle ABD is congruent to triangle CDB", is that right? If so, use the parallel lines AB and DC to get another pair of equal angles, then use AAS (angle, angle, side) to prove congruence.