# Prove that segment BC is congruent to segment AD? Relevance
• The given conditions are not clear. I understand your problem as that

AB // CD

are given, & prove that BC=AD. If so, then

Proof:

BD=BD (common sides equal)

Thus, Tri. BCD is congruent to tri. DAB (A.S.A)

=>

BC=AD (the corresponding sides of 2 congruent triangles equal)

• Login to reply the answers
• Obviously, BC = AD, AB = DC,

• Login to reply the answers
• In the figure itself it is seen that the line segment BC

is equal to the line segment AD.

• Login to reply the answers
• Well, they are already given as congruent in the diagram so technically a proof is unnecessary.

If they weren't marked as congruent, you would say:

AB || CD --- Given

DB ≅ BD --- Reflexive property

∠ABD ≅ ∠CDB --- When a transversal (DB) cuts parallel lines, alternate interior angles are congruent.

△ADB ≅ △CBD --- ASA (angle-side-angle) triangle congruence postulate

BC ≅ AD --- Corresponding parts of congruent triangles are congruent (CPCTC)

Q.E.D.

• Login to reply the answers
• Anonymous
1 month ago

You have a parallelogram since by the alternate angle theorem, BC is parallel to AD.

Property of a parallelogram is that opposite sides are equal, so BC = AD

• Login to reply the answers
• Something is not right with the question, "congruent" is not used for line segments, only triangles (or other polygons), as far as I know. In the diagram it is given that the segments BC and AD are equal.

I'm assuming you meant "prove triangle ABD is congruent to triangle CDB", is that right? If so, use the parallel lines AB and DC to get another pair of equal angles, then use AAS (angle, angle, side) to prove congruence.

• qspeechc1 month agoReport
• Login to reply the answers