# Circuit interpretation?

Why is the 14 ohm resistor in the following circuit, which has a short circuit between terminals a and b, considered to be in series with the 6 ohm resistor but not the 5 ohm resistor? The current, which flows clockwise, is the same for all three resistors. The total resistance is 4 ohms.

Update:

Couldn't the circuit just be redrawn excluding the short circuit so the 14 ohm and 5 ohm resistor would exclusively be connected at a single node? Relevance
• Req = 5 // (14+6) = 20*5/25 = 4.0 ohm

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• The definition of "in series" is the same current. A voltage source across terminals a and b would result in different currents.

• aleem4 weeks agoReport

But the 14 ohm and 5 ohm resistors do have the same current in the circuit with a short circuit between a and b

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• The current isn't the same in all for all three resistors. It is two parallel branches. The current shown in the question is in the wrong direction in the 14, 6 branch.

Redraw... • Dixon
Lv 7
4 weeks agoReport

KVL Voltage round a loop is zero. KCL Net current into a node is zero (or equivalently, current in = current out)

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• The 5 ohm resistor is connected across nodes a and b.

Together the 6 ohm resistor and the 14 ohm resistor form a single series 20 ohm resistor across nodes a and b.

You have to first evaluate your voltage potentials before evaluating the rest of the circuit.

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