# a student starts at {0,0} and walks to {6,0} turns right and walks to {6,8} what is the total distance the student walked?

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• 6 units forwards and 8 units backwards...

Or an infinite distance, down to negative infinity, coming back down from positive infinity.

Or he turned left at (6,0)

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• 14..........................

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• The student should turn left at (6,0). To show a point we conventionally use (x,y)

known as the ordered pair, not {x,y} unless you define it & show its exact meaning.

The total distance=6+8=14.

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write " why didn't you draw a picture on a piece of graph
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• A student starts at {0, 0} and walks to {6, 0}

turns left (not right) and walks to {6, 8}.

The total distance the student walked is 14 units.

• He must have turned left nor right  to reach {6,8}. The total distance walked is 14.

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• Hi, I'm wondering if you copied this question exactly as it appeared in the source.

There are two possibilities here:

1) How far did he/she walk? He walked 6 units in the x-direction; then i units in the y-direction for a total of 14 units.

2) What distance is he/she from the starting point? This is a right triangle with sides 6 and 8. So, you use the Pythagorean theorem to find the hypotenuse:

sqrt(6^2 +8^2) =10 units.

Hope this helps.

formeng

• The total distance should be 14; the displacement is 10.
One must make clear that. Thus the answer=14.

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• (0,0) to (6,0)

He walks 6 in the x coordinate and 0 in the y coordinate

(6,0) to (6,8)

He walks 0 in the x coordinate and 8 in the y coordinate

6 + 8 = 14

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• walked 14 but is only 10 units from the starting point

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• They went right 6 units. Then they went up 8 units.

You asked for the total distance the student walked which would just be the sum.

6 + 8 = 14 units

However, perhaps you meant to ask, how far they are from their starting point. If you imagine a right triangle, one leg would be 6 and the other would be 8. The hypotenuse would be the distance between the origin and the final point.

Use the Pythagorean Theorem:

6² + 8² = c²

36 + 64 = c²

c² = 100

c = √100

c = 10

14 units walking and now they are 10 units from their starting point.

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• apply distance formula

d1 = √[(6 - 0)^2 + (0 - 0)^2] = 6 units

d2 = √[(6 - 6)^2 + (8 - 0)^2] = 8 units

total distance = d1 + d2 = 6 + 8 = 14 units  answer//

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• distance between (0, 0) and (6, 0) is 6 units

distance between (6, 0) and (6, 8) is 8 units

total distance = 6 + 8 = 14 units

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