Skylar asked in Science & MathematicsMathematics · 2 months ago

# Stat Help!?

Find the following probabilities for the standard normal random variable z:

(a) P(−1.68≤z≤2.23)=

(b) P(−0.97≤z≤2.01)=

(c) P(z≤0.27)=

(d) P(z>−1.45)=

How do I go about figuring these out? I'm so confused and my professor isn't much help.

Relevance
• Alan
Lv 7
2 months ago

since you figured out the last two.

P(  A<z<B) = P(z<B) - P(z<A)

a) P(−1.68≤z≤2.23)=

so this becomes

P(−1.68≤z≤2.23)= P(z< 2.23) - P(z< -1.68)

so you now just need to find

P(z< 2.23) and P(z< -1.68)

(b) P(−0.97≤z≤2.01)=

P(−0.97≤z≤2.01) = P(z< 2.01) - P(z< -0.97)

again you should know how to find

P(z<2.01)   and P(z< -0.97)

• 2 months ago

I'm sending you the answer for the first one, you need to add the probabilities seen in the attached picture i.e. 45.35% + 48.71% = 94.06%

• alex
Lv 7
2 months ago

Just know how to input data in your calculator

a/

0.9406

b/

0.8118

c/

0.6064

d/

0.9265

• Mary
Lv 4
2 months ago

you need to look at a z-score table. find the values in the table and you will have your answers.

• ...Show all comments
• Mary
Lv 4
2 months agoReport

You have to write it the same way as it is written. You're just stating that the z score is within the values , its not a specific value, but a value within two others