# help me solve this equation: 3^2 * (5-7) - 55+65 - 6^5 *6/5 + 88- 69 *77^5=?

### 2 Answers

- llafferLv 72 months agoFavorite Answer
3² * (5 - 7) - 55 + 65 - 6⁵ * 6 / 5 + 88 - 69 * 77⁵

First, we simplify what's in parenthesis. There is only one set so we do that subtraction:

3² * (-2) - 55 + 65 - 6⁵ * 6 / 5 + 88 - 69 * 77⁵

Next, we resolve any exponents. We have two values to the fifth power and one value to the second power:

9 * (-2) - 55 + 65 - 7776 * 6 / 5 + 88 - 69 * 2706784157

Next we do any multiplications and divisions in order from left to right:

-18 - 55 + 65 - 7776 * 6 / 5 + 88 - 69 * 2706784157

-18 - 55 + 65 - 46656 / 5 + 88 - 69 * 2706784157

-18 - 55 + 65 - 9331.2 + 88 - 69 * 2706784157

-18 - 55 + 65 - 9331.2 + 88 - 186768106833

Finally, add and subtract in order from left to right:

-73 + 65 - 9331.2 + 88 - 186768106833

-8 - 9331.2 + 88 - 186768106833

-9339.2 + 88 - 186768106833

-9251.2 - 186768106833

-186,768,116,084.2

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- KrishnamurthyLv 72 months ago
3^2 * (5 - 7) - 55 + 65 - 6^5 *6/5 + 88 - 69 *77^5

= -18 - 55 + 65 + 88 - (6^6/5 + 69*77^5)

= 80 - 933840580821/5

= -933840580421/5

= -186768116084 1/5

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