A cylindrical roll of sod is being unrolled such that its volume is decreasing at a rate of 2500 cm^3/s. If the length of the roll is ?

45 cm, at what rate is the radius of the roll decreasing when it has reached a radius of 12.5 cm? 

1 Answer

  • Bryce
    Lv 7
    3 months ago
    Favorite Answer

    V= π*r^2*h, h= 45 cm

    dV/dt= 90πr*dr/dt

    2500= 90π*12.5*dr/dt

    dr/dt= 250/(112.5π)≈ 0.7074 cm/s

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