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# A circle has its center at the point (5, -3) and goes through the point (-1, 4). Give the equation for the circle.?

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- Engr. RonaldLv 72 months ago
Apply this formula

(x - a)^2 + (y - b)^2 = r^2

(-1 - 5)^2 + (4 - (-2))^2 = r^2

(-6)^2 + 6^2 = r^2

36 + 36 = r^2

r^2 = 72

the equation of the circle is

(x - 5)^2 + (y + 3)^2 = 72

x^2 - 10x + 25 + y^2 + 6y + 9 = 72

x^2 - 10x + y^2 + 6y + 34 - 72 = 0

x^2 - 10x + y^2 + 6y - 38 = 0 answer//

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- alexLv 72 months ago
C(5, -3) , A(-1, 4) ---> radius r = CA

formula

A(a,b) , B(c,d) --> distance AB = √[(a-c)^2+(b-d)^2]

Circle center (h,k) , radius = r

--->equation (x-h)^2+(y-k)^2=r^2

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