Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

A circle has its center at the point (5, -3) and goes through the point (-1, 4). Give the equation for the circle.?

2 Answers

Relevance
  • 2 months ago

    Apply this formula

    (x - a)^2 + (y - b)^2 = r^2

    (-1 - 5)^2 + (4 - (-2))^2 = r^2

     (-6)^2 + 6^2 = r^2

     36 + 36 = r^2

     r^2 = 72

     

    the equation of the circle is

    (x - 5)^2 + (y + 3)^2 = 72

    x^2 - 10x + 25 + y^2 + 6y + 9 = 72

    x^2 - 10x + y^2 + 6y + 34 - 72 = 0

     x^2 - 10x + y^2 + 6y - 38 = 0 answer//

    • Commenter avatarLogin to reply the answers
  • alex
    Lv 7
    2 months ago

    C(5, -3) , A(-1, 4) ---> radius r = CA

    formula

    A(a,b) , B(c,d) --> distance AB = √[(a-c)^2+(b-d)^2]

    Circle center (h,k) , radius = r

    --->equation (x-h)^2+(y-k)^2=r^2

    • Commenter avatarLogin to reply the answers
Still have questions? Get your answers by asking now.