Physics pls help me?
I've been trying to figure out how to solve this, but I can't!
Here is the problem:Sam, with a mass of 64 kg was playing field hockey when she tripped and fell. If her initial velocity was 3.2 m/s [E] and she slid 2.8 m before coming to rest, determine the coefficient of kinetic friction between the grass and Sam.
- FiremanLv 79 months agoFavorite Answer
Let the coefficient of kinetic friction between the grass and Sam is µk, now by the work energy relation:
=>∆W = KE
=>F(friction) x s = 1/2mv^2
=>(µk x mg) x s = 1/2mv^2
=>µk = v^2/(2 x g x s)
=>µk = (3.2)^2/[2 x 9.8 x 2.8]
=>µk = 0.19
- oubaasLv 79 months ago
m*V^2 = 2*m*g*μ*d
mass m cross
μ = V^2 / (2*g*d) = 3.2^2/(19.61*2.8) = 0.186