# what pressure will 3.20 mol of nitrogen gas exert if confined in a 15 L container at 100 C?

R=0.0821 L atm/mol K

13 atm

1.75 atm

6.53 atm

3.27 atm

150 atm

### 1 Answer

Relevance

- Roger the MoleLv 79 months ago
P = nRT / V = (3.20 mol) x (0.0821 L atm/mol K) x (100 + 273) K / (15 L) = 6.53 atm

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