Trig identities Help?

Which expression is equivalent to (cosθ) / (1 + sinθ)

a)   cosθ(1 + sinθ) / (1 + sin^2 θ)

b)   (cosθ) / (1 - sinθ)   

c)   (1 - sinθ) / (cosθ)

d)   (1 + sinθ) / (cosθ)

WILL AWARD BEST ANSWER!!!

Thanks so much, please show work.

2 Answers

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  • 6 months ago
    Favorite Answer

    Multiply the expression by (1-sinθ) / (1-sinθ) to give:

    cosθ(1-sinθ) / (1 - (sinθ)^2) = cos(θ)(1-sinθ) / (cosθ)^2 = (1-sinθ) / cosθ Answer C

  • 6 months ago

    The answer is C. I initially tried this problem by substituting values in for theta in the original expression and then substituting the same values in for theta in all of the choices. C is the only answer choice that yielded a similar result.

    Also, MAGA 2020

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