Trig Identities help?

Which expression is equivalent to (1 - 2sin^2 θ)

a)   cos^2 θ

b)   2cos^2 θ - 1

c)   1 - 2cos^2 θ 

d)   sin^2 θ

WILL AWARD BEST ANSWER!!!

Thanks so much, please show work.

Update:

work not required**

1 Answer

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  • 5 months ago

    1 - 2 sin^2(theta)

    = (1 - sin^2(theta)) - sin^2(theta)

    = cos^2(theta) - sin^2(theta)

    = cos^2(theta) - (1 - cos^2(theta))

    = 2 cos^2(theta) - 1. B).

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