If 3.00 mol of C3H6O is combusted with 7.00 mol of oxygen, how many moles of excess reactant are left over?

If 3.00 mol of C3H6O is combusted with 7.00 mol of oxygen, how many moles of excess reactant are left over?

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  • Anonymous
    6 months ago

    Always start with the balanced equation

  • 6 months ago

    C3H6O + 4 O2 → 3 CO2 + 3 H2O

    7.00 moles of O2 would react completely with 7.00 x (1/4) = 1.75 moles of C3H6O, but there is more C3H6O present than that, so C3H6O is in excess.

    (3.00 mol C3H6O initialy) - (1.75 mol C3H6O reacted) = 1.25 mol C3H6O left over

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