Find the number of neutrons released when 132 Sn and 101 Mo are released as fission fragments.?



235 U

1 Answer

  • 5 months ago
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    Fission fragments from what? Without knowing the original nucleid, there is no way to know. You can figure out the original element, though:

    132/50 Sn and 101/42 Mo mean that the atomic number of the original nucleid (assuming fission was induced by a neutron) would have to be ?/92U. 

    Assuming that the original isotope was 235/92 U and fission was induced by one neutron, that would give 236 - (132+101) = 3. 

    So, 3 neutrons would have been released in this fission.

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