A car drives off a 25 m tall bridge travelling at a horizontal velocity of 25 m/s?

a) How far does it travel from the bridge?

b) How long is the car in the air? 

4 Answers

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  • 1 month ago
    Favorite Answer

    Let the car take t sec to fall 25m

    =>By s = ut + 1/2gt^2

    =>25 = 0 + 1/2 x 9.8 x t^2

    =>t = √5.10

    =>t = 2.26 sec -----------------Answer for (B)

    Now let the car cover R meter horizontally in 2.26 sec

    Thus by s = ut

    =>R = 25 x 2.26 

    =>R = 56.47 m -----------------Answer for (A)

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  • 1 month ago

    Why?  If I was travelling at 90 km/hr I would not attempt to drive off the side of a bridge.  Was the driver on the mobile phone?  Was another vehicle involved?  Many questions should be asked that are more important than where the car landed.

    t= sqrt( 2 h / g) = 2.26 s  and distance = vt

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  • Jim
    Lv 7
    1 month ago

    y(t) = ½at² + v₀t  + y₀ is the basic formula you need to know.

    Standard gravity is -9.80665 m/s²

    This will find time of flight.

    Then multiply by 25m/s for distance horizontal

    • Andrew Smith
      Lv 7
      1 month agoReport

      Ah but "standard gravity" only applies to one place and one time.  So one should not presume such accuracy unless it is actually specified.  It varies by more than this at different times of the tides.

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  • Dylan
    Lv 6
    1 month ago

    Solve b first. 

    b) 0.5*9.81*t^2 = 25

    a) s = 25*t

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