A car drives off a 25 m tall bridge travelling at a horizontal velocity of 25 m/s?
a) How far does it travel from the bridge?
b) How long is the car in the air?
- FiremanLv 71 month agoFavorite Answer
Let the car take t sec to fall 25m
=>By s = ut + 1/2gt^2
=>25 = 0 + 1/2 x 9.8 x t^2
=>t = √5.10
=>t = 2.26 sec -----------------Answer for (B)
Now let the car cover R meter horizontally in 2.26 sec
Thus by s = ut
=>R = 25 x 2.26
=>R = 56.47 m -----------------Answer for (A)
- Andrew SmithLv 71 month ago
Why? If I was travelling at 90 km/hr I would not attempt to drive off the side of a bridge. Was the driver on the mobile phone? Was another vehicle involved? Many questions should be asked that are more important than where the car landed.
t= sqrt( 2 h / g) = 2.26 s and distance = vt
- JimLv 71 month ago
y(t) = ½at² + v₀t + y₀ is the basic formula you need to know.
Standard gravity is -9.80665 m/s²
This will find time of flight.
Then multiply by 25m/s for distance horizontal
- DylanLv 61 month ago
Solve b first.
b) 0.5*9.81*t^2 = 25
a) s = 25*t